>>> round(1.255, 2)
1.25

A bug in Python interpreter?


Shold have been:

>>> round(1.255, 2)
1.26

In mathematics, the .5 part is always rounded up, so in the example the .255 should be rounded to .26 so please fix this bug.

No, just a result of the finite machine representation of
floats:

>>> repr(1.255)
'1.2549999999999999'

so the machine representation of 1.255 is actually less
than that value and round() is doing the right thing.

Gee, thanks for the insight. I didn't thought about the fact that binary floating point is so imprecise and can cause the round() to "error" in some situations.

In this case, the representation and the actual value are (way) off. How can that be? There are just 3 decimal numbers (.255) and Python at parsing the float is already off at the third decimal number. I'll never trust round() again. Well, actually I trust round() to do its job well -- it's the binary floating point I'm affraid of!

We must implement the decimal API to the core of Python in order to have precision.

Maybe something like http://docs.python.org/library/decimal ?

Retro> I didn't thought about the fact that binary floating point is so
    Retro> imprecise and can cause the round() to "error" in some
    Retro> situations.

Details on the limitations of floating point arithmetic are here:

    http://docs.python.org/tutorial/floatingpoint.html

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Please note that the error is not in the third decimal position, but only in the 16th (i.e. the difference between the intended value and the actual value is smaller than 0.0000000000000001).